Eye's on the New Horizons and the Kuiper Belt
- Physical & Life Sciences
- 344 Replies
So, should we use a torus volume formula to do the math? Dang, that article is so confusing, and beyond what I know about distribution. If I can figure out how many thousands/millions/billions of Kuiper Belt object > 10 km in diameter, the inner radius of the Kuiper Belt, the outer radius and the thickness, then I might be able to determine how many Kuiper belt objects > 10 km in diameter there could be in a cubic AU of space. Then, one could calculate the mean distance between a Kuiper belt object and New Horizons at any given point in time?A search of google scholar (Kuiper belt size distribution) produced this article, The size distribution of Kuiper Belt objects for D >10 km as the second hit. Judicious amendments to the search prompt and date range should provide improved selections. Then it's just a bit of maths. Do keep in mind that the Kuiper Belt is a volume, not a plane.
After that, how do we calculate the probability of a flyby within say 10,000 km or say 384,400 km (one lunar distance) of a Kuiper Belt object >10 km in diameter? Do we just cube that distance, and divide it by the total volume of the Kuiper Belt and multiply by the number of objects in the Kuiper belt?
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