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Discussion and Debate
Discussion and Debate
Physical & Life Sciences
Non-Mainstream and Controversial Science
Has Geocentrism become less popular?
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<blockquote data-quote="sjastro" data-source="post: 77392092" data-attributes="member: 352921"><p>The two pieces of evidence which support metric expansion of distant non gravitationally bound galaxies instead of galaxies moving in space are;</p><p></p><p>(1) The galaxies are moving along the line of sight of the observer there is no transverse or perpendicular component of motion relative to the observer.</p><p>(2) The recession velocity v is proportional to distance x, the proportionality constant being Hubble’s constant H, v = Hx.</p><p>This is Hubble’s law.</p><p></p><p style="text-align: center"><img src="https://astrobites.org/wp-content/uploads/2016/04/hubbleslawdiagram.gif" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p>In the case of point (1), if all galaxies move in space instead of metric expansion, then we would expect to also observe a transverse or perpendicular component of motion even in the most distant galaxies as a deviation from the straight line relationship for Hubble’s law.</p><p>In fact, there is no reason to even suggest recession velocities should occur exclusively, in our<a href="https://en.wikipedia.org/wiki/Local_Group" target="_blank"> Local Group</a> not only do transverse motions occur but the spectra of galaxies such as the Andromeda galaxy are blue shifted indicating they are approaching the observer not receding.</p><p></p><p>For point (2) the straight line relationship between velocity and distance is exclusively a property of metric expansion, there is no way we can even show mathematically how a straight line relationship for velocity and distance can occur for galaxies accelerating through space.</p><p>We can show this by using the simplest example of constant acceleration at non relativistic speeds using calculus and high school physics.</p><p>Since the acceleration a is constant for the velocity v at time t and using the initial conditions v=0 at x=0 for a Big Bang condition.</p><p></p><p>[ATTACH=full]336878[/ATTACH]</p><p></p><p>The general graph for constant acceleration at non relativistic speeds in space does not have a straight line relationship as shown.</p><p></p><p style="text-align: center">[ATTACH=full]336879[/ATTACH]</p><p></p><p>For more complicated cases such as non constant acceleration and/or relativistic speeds the graphs are far more complex.</p></blockquote><p></p>
[QUOTE="sjastro, post: 77392092, member: 352921"] The two pieces of evidence which support metric expansion of distant non gravitationally bound galaxies instead of galaxies moving in space are; (1) The galaxies are moving along the line of sight of the observer there is no transverse or perpendicular component of motion relative to the observer. (2) The recession velocity v is proportional to distance x, the proportionality constant being Hubble’s constant H, v = Hx. This is Hubble’s law. [CENTER][IMG]https://astrobites.org/wp-content/uploads/2016/04/hubbleslawdiagram.gif[/IMG][/CENTER] In the case of point (1), if all galaxies move in space instead of metric expansion, then we would expect to also observe a transverse or perpendicular component of motion even in the most distant galaxies as a deviation from the straight line relationship for Hubble’s law. In fact, there is no reason to even suggest recession velocities should occur exclusively, in our[URL='https://en.wikipedia.org/wiki/Local_Group'] Local Group[/URL] not only do transverse motions occur but the spectra of galaxies such as the Andromeda galaxy are blue shifted indicating they are approaching the observer not receding. For point (2) the straight line relationship between velocity and distance is exclusively a property of metric expansion, there is no way we can even show mathematically how a straight line relationship for velocity and distance can occur for galaxies accelerating through space. We can show this by using the simplest example of constant acceleration at non relativistic speeds using calculus and high school physics. Since the acceleration a is constant for the velocity v at time t and using the initial conditions v=0 at x=0 for a Big Bang condition. [ATTACH type="full"]336878[/ATTACH] The general graph for constant acceleration at non relativistic speeds in space does not have a straight line relationship as shown. [CENTER][ATTACH type="full"]336879[/ATTACH][/CENTER] For more complicated cases such as non constant acceleration and/or relativistic speeds the graphs are far more complex. [/QUOTE]
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